Details

Written by Stanko Milosev

Category: C#

Published: 24 December 2019

Hits: 97

To write this article I was using this web site.

First create JSON configuration file, in my case I did it like this:

Right click on file, and click properties:

Set "Copy to Output Directory", in my case I have set it to "Copy always":

Add following references:

Microsoft.Extensions.Configuration
Microsoft.Extensions.Configuration.FileExtensions
Microsoft.Extensions.Configuration.Json

In my case I have added them with NuGet:

Or you can add them via console:

dotnet add package Microsoft.Extensions.Configuration
dotnet add package Microsoft.Extensions.Configuration.FileExtensions
dotnet add package Microsoft.Extensions.Configuration.Json

In my case my JSON configuration file looks like this:

{
"apiKey":  "myApiKey"
}

Code:

using Microsoft.Extensions.Configuration;
using System;
using System.IO;

namespace jsonConfigurationFile
{
  class Program
  {
    static void Main(string[] args)
    {
      IConfiguration config = new ConfigurationBuilder()
          .AddJsonFile("jsconfig1.json", true, true)
          .Build();

      Console.WriteLine($" Key: { config["apiKey"] }");
      Console.ReadKey();
    }
  }
}

Details

Written by Stanko Milosev

Category: C#

Published: 22 December 2019

Hits: 83

Recently I was trying to deserialize JSON which I have received from Google Reverse Geocoding (Address Lookup). First I was playing with example which is described here, but I didn't like that method, since it is too complicated. In order to deserialize JSON into an object, first I have to create that object, and in case of Google it is too complicated. Here is my partial solution, when I definitely decided to give up. I needed name of the city, and state of location:

using (JsonDocument document = JsonDocument.Parse(doc))
{
	Console.WriteLine($"plus_code: {document.RootElement.GetProperty("plus_code")}");
	foreach (JsonElement element in document.RootElement.GetProperty("results").EnumerateArray())
	{
		foreach (JsonElement addComp in element.GetProperty("address_components").EnumerateArray())
		{
			Console.WriteLine($"long_name: {addComp.GetProperty("long_name")}, short_name: {addComp.GetProperty("short_name")}");
			foreach (JsonElement type in addComp.GetProperty("types").EnumerateArray())
			{
				Console.WriteLine($"type: {type.ToString()}");
			}
		}
	}
}

I have decided to go further using this (Newtonsoft.Json) solution. Just with one line of code:

JObject myJObject = JObject.Parse(doc);

I have basically extracted everything I need.

Details

Written by Stanko Milosev

Category: C#

Published: 15 December 2019

Hits: 96

From Microsoft web site:

In a generic type or method definition, a type parameter is a placeholder for a specific type that a client specifies when they create an instance of the generic type. A generic class, such as GenericList listed in Introduction to Generics, cannot be used as-is because it is not really a type; it is more like a blueprint for a type.

In my case I wanted to have two different generic list names, generated from different classes, but those classes would be inherited from one class, something like this:

  class IDName
  {
    public Guid ID;
    public string Name;
  }

  class FirstIDName: IDName { }
  class SecondIDName : IDName { }

Then I need one method to fill those classes:

public static void AddToIDName<T>(List<T> iDNameList, string name) where T : IDName, new()
{
  iDNameList.Add(new T
  {
	ID = Guid.NewGuid(),
	Name = name
  });
}

Here notice constraint "where T : IDName, new()". I needed constraint new because of line: "iDNameList.Add(new T"

Whole example:

using System;
using System.Collections.Generic;

namespace GenericList
{
  class Program
  {
    static void Main(string[] args)
    {
      List<FirstIDName> firstIDNames = new List<FirstIDName>();
      List<SecondIDName> secondIDNames = new List<SecondIDName>();

      AddToIDName(firstIDNames, "firstIDNameTestOne");
      AddToIDName(firstIDNames, "firstIDNameTestTwo");

      AddToIDName(secondIDNames, "secondIDNameTestOne");
      AddToIDName(secondIDNames, "secondIDNameTestTwo");
      AddToIDName(secondIDNames, "secondIDNameTestThree");

      Console.WriteLine("FirstIDName");
      foreach (FirstIDName firstIDName in firstIDNames)
      {
        Console.WriteLine($"id: {firstIDName.ID}, name: {firstIDName.Name}");
      }

      Console.WriteLine("SecondIDName");
      foreach (SecondIDName secondIDName in secondIDNames)
      {
        Console.WriteLine($"id: {secondIDName.ID}, name: {secondIDName.Name}");
      }

      Console.WriteLine("");
      Console.WriteLine("The end");
      Console.ReadKey();
    }

    public static void AddToIDName<T>(List<T> iDNameList, string name) where T : IDName, new()
    {
      iDNameList.Add(new T
      {
        ID = Guid.NewGuid(),
        Name = name
      });
    }
  }
}